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Find the second maximum in an array?

Answers were Sorted based on User's Feedback

Find the second maximum in an array? ..

Answer / jagdish patel

it's simple just sort an array in descending and then
print 2nd element of an array!!!!

 Is This Answer Correct ? 27 Yes 8 No

Find the second maximum in an array? ..

This will fail if the input array is {-1,-2,-3}

 Is This Answer Correct ? 17 Yes 7 No

Find the second maximum in an array? ..

int SecondMax(int *Array, int ACount)
{
int Fm = 0, Sm = 0;
for (int i = 0; i < ACount; i++)
{
if (Array[i] > Sm)
{
if (Array[i] < Fm) Sm = Array[i];
else
{
Sm = Fm;
Fm = Array[i];
}
}
}
return Sm;
}

 Is This Answer Correct ? 31 Yes 22 No

Find the second maximum in an array? ..

int sec_max(int a[])
{
if(a[0]>a[1])
{
max=a[0]
sec_max=a[1]
}
else
{
max=a[1]
sec_max=a[0]
}
for(i=1;i<n-1;i++)
{
if (a[i]>sec_max && a[i]< max)
{
sec_max=a[i];
}
else if(a[i]>max)
{
sec_max=max;
max=a[i];
}
return sec_max;
}

 Is This Answer Correct ? 5 Yes 1 No

Find the second maximum in an array? ..

public void getSecondMax(double[] arr){
double fmax, smax;
fmax=arr[0];
smax=arr[1];

for (int i = 1; i < arr.length; i++) {
if (arr[i]>fmax){
smax = fmax;
fmax = arr[i];
}
else if (arr[i]>smax)
smax = arr[i];

}

System.out.println("The 1st
highest="+fmax+"\t"+"The 2nd highest="+smax);
}

Note that it would not work if the array's size is only 1.

 Is This Answer Correct ? 4 Yes 2 No

Find the second maximum in an array? ..

int SecondMax(int Array[], int ALength)
{
int Fmax,Smax;
Fmax=Smax=Araay[0];
for (int i = 0; i < ALength; i++)
{
if (Array[i] > Smax){
if (Array[i] < Fmax){
Smax = Array[i];
}
else{
Smax = Fmax;
Fmax = Array[i];
}
}
}
return Smax;
}

 Is This Answer Correct ? 9 Yes 8 No

Find the second maximum in an array? ..

/*Code to write second Minimum Number*/
int[] intarr = { 2, 5, 1, 8, 3, 6, 0, 4, 3, 2, 78, 1, 8 };

int intminval = 0, intsecondminval = 0;

for (int i = 0; i < intarr.Length; i++)
{
if (i == 0)
{
intminval = intsecondminval = intarr[i];
}
else
{
if (intarr[i] < intminval)
{
intsecondminval = intminval;
intminval = intarr[i];

}
else if (intminval == intsecondminval && intarr[i] > intminval)
{
// this conditon is to handle the case
//where the array contains only 2 values
// for e.g. {1,1,2,1,2,2,1}
intsecondminval = intarr[i];
}
}
}

 Is This Answer Correct ? 5 Yes 6 No

Find the second maximum in an array? ..

This might help.

max1=a[0];max2=a[1];

for(i=1;i<n;i++)
{
if(max1<a[i])
{
max2=max1;
max1=a[i];
}

if(max2==max1) max2=a[i+1];

if(max2==a[n]) { printf("All numbers are the same no second max.\n"); return 0;}

if(max2<a[i] && max1!=a[i]) max2=a[i];
}

 Is This Answer Correct ? 0 Yes 1 No

Find the second maximum in an array? ..

int a1(int[] a)
{
int max1 = -1;
int max2 = -1;

for (int i=0; i<a.length; i++)
{
if (a[i] > max1)
{
max2 = max1;
max1 = a[i];
}
else if (a[i] != max1 && a[i] > max2)
max2 = a[i];
}

return max2;
}

 Is This Answer Correct ? 0 Yes 1 No

Find the second maximum in an array? ..

Answer / vinod, bangalore, india

int Second_Max(int* numbers, int Lenght)
{

int Max, Sec_Max, index;
Max = Sec_Max = numbers[0];
for(index=0; (index<Lenght) &&(Max == Sec_Max);
index++)
{
if(Max > numbers[index])
Sec_Max = numbers[index];
else
Max = numbers[index];
}
if(index == Lenght)
{
printf("Array contain simillar data and the
data is = %d \n", Max);
return false;
}

for(index =0; index < Lenght; index++)
{
if(numbers[index] > Max)
{
Sec_Max = Max;
Max = numbers[index];
}
if((numbers[index] < Max) && (numbers
[index] > Sec_Max))
{
Sec_Max = numbers[index];
}
}
return Sec_Max;
}

 Is This Answer Correct ? 2 Yes 7 No

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