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abcD+abcd+aBCd+aBCD
then the simplified function is
( Capital letters are copliments of corresponding letters
A=compliment of a)
[a] a [b] ab [c] abc [d] a(bc)* [e] mone
(bc)*=compliment of bc
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Answer / vijay
abcD+abcd+aBCd+aBCD
=> (abcD+abcd)+(aBCd+aBCD)
=> abc(D+d)+aBC(d+D)
=> abc(1)+aBC(1)
=> abc+aBC
=> a(bc+BC)
=> a(1)
=> a
//a is the answer.
| Is This Answer Correct ? | 12 Yes | 3 No |
Answer / shubh
abcD
+abcd
+aBCd
+aBCD
-------
=4a000
-------
so answer comes is 4a,but it is none of the given option so
answer is [e]
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / lt
okay, so we can get to "a(bc+BC)"
but "bc+BC" does not equal 1.
Think about it, if b=0.125 c=0.25; the B=0.875 and C=0.75
so... (0.03125)+(0.65625) = 0.6875.
So the answer is [e] (unless I missunderstood the meaning of
the notatiion in answer [d]).
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / ramya
since capital letters are the complements...
(abcD+abcd)+(aBCd+aBCD)..taking them separately...
solving for the 1st bracket...abc(D+d)=abc{D+d=0}
solving for the 2nd bracket...aBC(d+D)=aBC{D+d=0}
==abc+aBC=a(bc+BC)
=a*0
=0
| Is This Answer Correct ? | 3 Yes | 8 No |
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