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abcD+abcd+aBCd+aBCD
then the simplified function is
( Capital letters are copliments of corresponding letters
A=compliment of a)
[a] a [b] ab [c] abc [d] a(bc)* [e] mone
(bc)*=compliment of bc
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Answer Posted / vijay
abcD+abcd+aBCd+aBCD
=> (abcD+abcd)+(aBCd+aBCD)
=> abc(D+d)+aBC(d+D)
=> abc(1)+aBC(1)
=> abc+aBC
=> a(bc+BC)
=> a(1)
=> a
//a is the answer.
| Is This Answer Correct ? | 12 Yes | 3 No |
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