Answer / aditi joshi

let original radius=100
original surface area lets say it x =4 * (22/7) * 100 *100
new radius=100 + 50% of 100=150
new surface area lets say it y = 4 * (22/7)* 150* 150
increase in surface area=((y-x)/x) * 100
i.e.
((4*(22/7)*150*150 - 4*(22/7)*100 *100) / (4*(22/7)*100*100))*100
=125
so the answer is 125%.
hope this helps you.

Answer / saurabh

surface area will increase by 125%

and shruti u r wrong

Answer / arvind yeram

r1 = initial radius
r2 = final radius
s1 = 4πr1^2
s2 = 4πr2^2
r2 = 50/100r1+r1 = 3/2r1
s2 = 4π9/4r1^2
%increase = (9/4-1)*100
= 5/4*100
= 125

Answer / harsh goel

let the edge of cube be=x
the edge increased by 50%
=x+50÷100
=x(1+1/2)
=3x/2
orignal surface area=6x^2
new surface area of a cube=6(3x/2)^2
=6×9x^2/4
=27x^2/2
increased in area of cube=27x^2-12x^2/2
=15x^2/2
the percentage increased=increase in area/orignal area ×100
=15×100/2×6x^2
=1500/12x^2
=125%

Answer / satyam

1st sphere=x and 2nd sphere=y then
x=4(22/7)×100 50=4(22/7)150
y=4(22/7)×100=4(22/7)100
area={(x-y/x))r2
={4(22/7)150-4(22/7)100/4(22/7)100}r2
={4(22/7)50/4(22/7)100}r2
={50/100}r2
=.5×r2 ;0.5×0.5=0.25 = 100 25= 125%

Answer / brebis

surface area increases with radius by factor 4.

i.e. 200%

Answer / sruthi

The surface area is also incresed by 50%.

Answer / subbu

power of r in area is 2 so 2*50=100%

Answer / a.manikandan

98%

Answer / debanjana

radius is only half of the diameter, so the diameter should
be counted which is the surface area, so it should be 100%

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