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Radius of sphere is increased by 50%. By how much percentage
is surface area is increased?
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Answer Posted / arvind yeram
r1 = initial radius
r2 = final radius
s1 = 4πr1^2
s2 = 4πr2^2
r2 = 50/100r1+r1 = 3/2r1
s2 = 4π9/4r1^2
%increase = (9/4-1)*100
= 5/4*100
= 125
| Is This Answer Correct ? | 32 Yes | 16 No |
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