Answer / dharanidhar

P is a pointer which is constant. So, the values in this
array cannot be modified.

characters within a[] can be changed by accessing
like a[1] = '2',....

Answer / parmjeet kumar

char a[] will alocate the momery size of " string" word in
other hand char *p will alocate the memory size of one
character... or we can not move the data from one location
to another location but with pointer we can do it...

Answer / ashish

here a is an array and is a char const * data type.
hence u cannot change value of a but u can change the value
which a points to.
p on the other hand is a const char * data type.
hence value of p an be changed but the value p points to
cannot be changed.




i dont know the answer!!! :P

Answer / aravind

hi im answering as far as i know , pls say ur feedback,,,(+_+)
Array:
for char array char a[]; no such array size is accepted by
the compiler. That is , it requires a fixed size for the
array like: char a[20];

in this case the number of strings / characters it can hold
is only upto 20 while if it exceeds , the input strings get
truncated. [STATIC MEMORY ALLOCATION AND TRAVERSAL WITHIN
BOUNDS]

Pointer:
Whereas in case of pointers it is of DYNAMIC MEMORY type and
infinite storage when compared to Array. and predefinition ,
truncation are absent.
Also TRAVERSAL is easy.

second highest number in a given set of numbers

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int array[]={1,2,3,4,5,6,7,8}; #define SIZE (sizeof(array)/sizeof(int)) main() { if(-1<=SIZE) printf("1"); else printf("2"); }

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