int array[]={1,2,3,4,5,6,7,8};
#define SIZE (sizeof(array)/sizeof(int))
main()
{
if(-1<=SIZE) printf("1");
else printf("2");
}
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program prints "2"
Here sizeof returns unsigned int value
so sizeof(array)/sizeof(int)
=> 32(unsigned int)/4(unsigned int)
=> 8 (unsigned int value)
During comparison, the datatypes are different on both sides of if condition
-1(signed int) <= 8(unsigned int)
so by rule of type conversion in c,
signed int gets converted to unsigned int
hence expression becomes
0xFFFFFFFF(unsigned int equivalent of -1) <= 8(unsigned int)
Hence overall condition becomes FALSE
| Is This Answer Correct ? | 72 Yes | 6 No |
main() { int a,b; printf("%d,%d",scanf("%d%d",&a,&b)); } => do u mean above program's output... =>output will be:2,whatever you enter value for b. =>because scanf is a library fn which will return how many arguements it processes, and second value you are right mr.Satya but i found my self unable to understand that for the first time scanf returns the no of successful matches but how for the second time it returns the value of 'b'.while a function should return the same 'r' value every time.
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