Define the process of an interrupt operation in the 8086?

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Define the process of an interrupt operation in the 8086?..

Answer / Shudhanshu Sharma

In the Intel 8086 microprocessor, an interrupt is a signal that interrupts the current program execution to handle external events or conditions. The process of handling an interrupt consists of several steps:

1. Interrupt Request (IRQ): An external device asserts the IRQ line, signaling the microprocessor to temporarily halt its current operation and start the interrupt service routine (ISR).
2. Saving the Context: The processor saves the state of the CPU onto the stack (pushing flags, instruction pointer, and other general-purpose registers) so that it can return to the interrupted program after handling the interrupt.
3. Jump to ISR: The control unit jumps to the specified interrupt vector address in memory, which contains the starting address of the corresponding ISR for the interrupt source.
4. Interrupt Service Routine Execution: The ISR processes the external event or condition and performs any necessary actions to resolve it before returning control back to the interrupted program.
5. Restoring the Context: After the ISR completes, the CPU restores the saved context from the stack to return to the interrupted program at its previous state.

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