What does a function declared as pascal do differently?
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consider the following structure: struct num nam{ int no; char name[25]; }; struct num nam n1[]={{12,"Fred"},{15,"Martin"},{8,"Peter"},{11,Nicholas"}}; ..... ..... printf("%d%d",n1[2],no,(*(n1 + 2),no) + 1); What does the above statement print? a.8,9 b.9,9 c.8,8 d.8,unpredictable value
The variables are int sum=10,SuM=20; these are same or different?
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What will be printed as the result of the operation below: #include<..> int x; int modifyvalue() { return(x+=10); } int changevalue(int x) { return(x+=1); } void main() { int x=10; x++; changevalue(x); x++; modifyvalue(); printf("First output:%d\n",x); x++; changevalue(x); printf("Second output:%d\n",x); modifyvalue(); printf("Third output:%d\n",x); }
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