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Why doesn't the code "int a = 1000, b = 1000;
long int c = a * b;" work?
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Answer / larry
This won't work if int is a 16-bit size because 1000000 >
32767 (2 to the 15th - 1). It will work when int is a 32-
bit number. It will work if you cast a or b to a long.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / thirupathi reddy katkoori
Integer range exceeds if multiply both the variables the resultant value does not to store it. Due to exceeding the int range only we have to declare it as long int and the value is store in c
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / guest
You must manually cast one of the operands to (long).
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / vikraman85
I think mostly we should avoid assigning the variables while
declaring with the variables of another datatype..
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / komal
it wont work as we have to declare the variable 'b'
again...we can not declare it like int a=10,b=3;
it has to b like int a=10;
int b=6;
| Is This Answer Correct ? | 0 Yes | 4 No |
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