Answer / Ajit Kumar

In C, you can create a sparse matrix using dynamic memory allocation by defining a struct for the matrix elements and dynamically allocating memory for the non-zero elements. Here's an example:nn```cn#include <stdio.h> n#include <stdlib.h>nnstruct Matrix {n int row;n int col;n int value;n struct Matrix *next;n};nnvoid create_matrix(struct Matrix **head, int rows, int cols) {n *head = (struct Matrix *)malloc(sizeof(struct Matrix));n if (*head == NULL) {n printf("Memory error
");n return;n }n (*head)->row = 0;n (*head)->col = 0;n (*head)->value = 0;n (*head)->next = NULL;nn int i, j;n for (i = 1; i <= rows; ++i) {n for (j = 1; j <= cols; ++j) {n struct Matrix *new_node = (struct Matrix *)malloc(sizeof(struct Matrix));n if (new_node == NULL) {n printf("Memory error
");n return;n }n scanf("%d %d %d", &(new_node->row), &(new_node->col), &(new_node->value));n new_node->next = *head;n *head = new_node;n }n }n}nnvoid display(struct Matrix *head) {n struct Matrix *temp = head;n while (temp != NULL) {n printf("Row: %d, Column: %d, Value: %d
", temp->row, temp->col, temp->value);n temp = temp->next;n }n}nnint main() {n int rows, cols;n printf("Enter the number of rows and columns: ");n scanf("%d %d", &rows, &cols);n struct Matrix *head = NULL;n create_matrix(&head, rows, cols);n display(head);n return 0;n}n```

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