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A wire of resistance 24 ohms is bent in the form of a
circular ring. The effective resistance between the two
points on any diameter of the circle is
(1) 24 ohms
(2) 12 ohms
(3) 6 ohms
(4) 3 ohms
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Answer / nihal
As a diameter divides a circle exactly half a way, so the wire too is divided halvely. Thus the length of each 2 segments is half of original. Thus resistance of each is halved. As the 2 segments is between the same 2 points, the combination is parallel. Then,
R=(12*12)/(12+12)=6 ohms
| Is This Answer Correct ? | 22 Yes | 4 No |
Answer / prachi
khud dhood lo doosron ko kyon pareshaan kar rhe ho
by the way answer is 6 ohm as the diameter divides the
circle in 2 different parts so it divides the wire in 2
different parts and resistance becomes half
| Is This Answer Correct ? | 4 Yes | 3 No |
Answer / shahbaz khan
For resistance between two point of diameter (180degree) of circle
=180/360*24
=12 ohm
We got R1= 12 ohm
R2=R-R1
=24-12=12. [Given R=24]
Therefore effective resistance;
1/R=1/R1+ 1/R2
= 1/12 + 1/12
=1/6
R=6 ohm
Since Effective resistance is 6 ohm
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / swagger
kk...itll be 6 ohms between a and b
but the question says....ends of diameter
so the answer is 12ohms...
| Is This Answer Correct ? | 2 Yes | 9 No |
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