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One of the longest sides of the triangle is 20 m. The other side is 10 m. Area of the triangle is 80 m2m2. What is the another side of the triangle?
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Given a triangle ABC, how would you use only a compass and straight edge to find a point P such that triangles ABP, ACP and BCP have equal perimeters? (Assume that ABC is constructed so that a solution does exist.)
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