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Given a triangle ABC, how would you use only a compass and
straight edge to find a point P such that triangles ABP, ACP
and BCP have equal perimeters? (Assume that ABC is
constructed so that a solution does exist.)
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Answer / koushik
The answer probably lies in finding the in-centre of the
traingle. Bisect all the angles of the triangles and the
point where these angle bisectors meet gives u the point P
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / vasudev
take a equilateral 3angle.... place compass pt @ each vertices.. draw an arc... mark d pt wr all arcs meet.. thats d pt P ..... thus it gives 3angle of equal perimeter
| Is This Answer Correct ? | 3 Yes | 0 No |
0.75 * 0.75 * 0.75 - 0.001 0.75*0.75-0.075+0.01
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