A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:



A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B..

Answer / Arun Kumar Shrivastava

Let's assume that A's successful rate is 1/3 and B's successful rate is 1/2. In this case, both A and B have missed a total of 27 shots. Let x be the number of shots fired by A:
5 * (1/3) + x = 27
Solving for x, we get:
x = 18 - (5 * 1/3)
Approximately, A has killed 13 shots

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