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study the code:
#include<stdio.h>
void main()
{
const int a=100;
int *p;
p=&a;
(*p)++;
printf("a=%dn(*p)=%dn",a,*p);
}
What is printed?
A)100,101 B)100,100 C)101,101 D)None of the
above
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Answers were Sorted based on User's Feedback
Answer / santhoo035
d)None of the above
It will give compliation error at the line p=&a,pointer to
integer cannot assign to const int
| Is This Answer Correct ? | 18 Yes | 1 No |
Answer / madhu
D) NONE OF THE ABOVE
COZ
ANS IS A=101n (*p)=101n
to get this *p should be an constant pointer
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / sridevi.halli
answer is d)none of the above
bcoz in line p=&a it will gve error
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / abdur rab
the answer is c) 101, 101
a constant variable can be accessed using a pointer to
change the value because, during compilation the compiler
cannot see that the pointer is changing a contant read only
variable.
the same method can be applied over the private members in
a c++ class also.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / biranchi ranjan parida
none of the above
pointer value of address increases it cant store its
original value
| Is This Answer Correct ? | 0 Yes | 1 No |
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