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study the code:
#include<stdio.h>
void main()
{
const int a=100;
int *p;
p=&a;
(*p)++;
printf("a=%dn(*p)=%dn",a,*p);
}
What is printed?
A)100,101 B)100,100 C)101,101 D)None of the
above
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Answer Posted / biranchi ranjan parida
none of the above
pointer value of address increases it cant store its
original value
| Is This Answer Correct ? | 0 Yes | 1 No |
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