A question for all cricket lovers and friends. .!!How many runs a single player can score in One day match (50 overs/ 300 balls)...No 'no balls', no wides, no extras, no over throws...So how much runs he can score max???this quetion came in CSAT and 99% people answered it wrong..Clue: the answer is not 1800.
Answers were Sorted based on User's Feedback
Answer / muhammad irfan qureshi
The correct answer is 1653
B'coz a player will make 33 runs in an over b'coz he can not play again if he made 36.
so 33 in an over then 1617 in 49 overs
and in last over he can made 36 runs
1617 + 36 = 1653 runs
Is This Answer Correct ? | 173 Yes | 32 No |
Answer / premr
The answer will 828 runs as 1 slected player will play only 25 overs in a day of 50 overs and there is exchange of players in every 1 over. So if 25th over he play then he score total 36 runs but at anoter overs he can 33 so 24×33=792. At last over 36 runs so
792+36=828
Is This Answer Correct ? | 3 Yes | 9 No |
Answer / deepak kale
If the player will play 5*6=30, and he will change the strike and play continue than it becomes 5*6+1=31 and total will be 1550.
Is This Answer Correct ? | 1 Yes | 7 No |
Answer / abhishek divekar
Well according to me there is max run we get is 6 run and for strike change we can run max 5 run on last bowl. So max Run in per over till 49 is 35. 35x49 = 1715. 1715 +36 = 1751.
Is This Answer Correct ? | 1 Yes | 12 No |
Alok and Bhanu play the following min-max game. Given the expression N = X - Y – Z where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be • 4 • -18 • 9 • 2
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