if there is any string in a given format like as "company name employeecod

if there is any string in a given format like as "company
name employeecode date" then we have to fetch employeecode
form string
for ex-string is "capgemini12345june2013" then we have to
fetch 12345 by using vb script so guys how can we do that
please reply it.

Question Posted / navdeep

3 Answers
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Cap Gemini, I also Faced
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if there is any string in a given format like as "company name employeecode date" then we..

Answer / suman

Str = "capgemini12345une2013"
Dim i, j
For i = 1 to Len(Str)
If isnumeric(Mid(Str, i, 1)) Then
Exit For
End If
Next
MsgBox i

For j = i to Len(Str)
If not isnumeric(Mid(Str, j, 1)) Then
Exit For
End If
Next
MsgBox j
MsgBox Mid(Str, i, (j - i))

Is This Answer Correct ?

5 Yes

0 No

if there is any string in a given format like as "company name employeecode date" then we..

Answer / abhijit bongale

Option Explicit

Dim Str : Str = "capgemini12345june2013"
Dim i, j

For i = 1 to Len(Str)
If Asc(Mid(Str, i, 1)) >= 48 AND Asc(Mid
(Str, i, 1)) <= 57 Then
Exit For
End If
Next

MsgBox i

For j = i to Len(Str)
If (Asc(Mid(Str, j, 1)) >= 65 AND Asc(Mid
(Str, j, 1)) <= 90) OR (Asc(Mid(Str, j, 1)) >= 97 AND Asc
(Mid(Str, j, 1)) <= 122) Then
Exit For
End If
Next

MsgBox j

MsgBox Mid(Str, i, (j - i))

Set Str = Nothing

Is This Answer Correct ?

1 Yes

1 No

if there is any string in a given format like as "company name employeecode date" then we..

Answer / sriraja

str="capgemini12345june2016"
strsplit=split(str,"june")
convstr=cstr(strsplit(0))
for i=1 to len(convstr)
strmid=mid(convstr,i,1)
if isnumeric(strmid)=true Then
temp=temp&strmid
End if
Next
Print temp

Is This Answer Correct ?

0 Yes

0 No

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