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#include<stdio.h>
main(0
{
printf("\n %d %d %d",sizeof(3),sizeof("3"),sizeof(3));
}
- 4 Answers
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Answer / nithya
the above code output is
syntax error
this code will be change from
#include<stdio.h>
main()
{
printf("\n %d %d %d",sizeof(3),sizeof("3"),sizeof(3));
}
the out put is
222
| Is This Answer Correct ? | 9 Yes | 1 No |
Answer / a.c.pattanaik
code is error due to declaration
if code is this
main()
{
printf("\n %d %d %d",sizeof(2),sizeof("a"),sizeof(2));
}
Ans-4 2 4
| Is This Answer Correct ? | 9 Yes | 5 No |
Answer / abhishek kumar verma
you have made a typing mistake if code will be this
#include<stdio.h>
main()
{
printf("\n %d %d %d",sizeof(3),sizeof("3"),sizeof(3));
}
then output will be 4 2 4
because in first it will print the size of an integer and in second it will print the size of an string and in third it will print the size of integer again .
| Is This Answer Correct ? | 4 Yes | 5 No |
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