write a non recursive shell script that accepts any number
of arguments and prints them in the reverse order
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Answer / naresh babu
echo "no of arguments:$#"
echo "arguments in reverse order:"
for i in $*
do
j=$i" "$j
done
echo $j
| Is This Answer Correct ? | 26 Yes | 9 No |
Answer / drths
$ sh rev.sh 123 ---Script name with 1 cmd line argument
------------------------------
#! /bin/sh
abc=$1 ###123 will store in abc
pqr=`echo $pqr | rev` ### 123|rev
echo $abc
-----------------------------
o/p : 321
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / amar
./reverse frg gh rtyh
no of arguments:3
arguments in reverse order:
rtyh gh frg
| Is This Answer Correct ? | 0 Yes | 8 No |
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