echo "no of arguments:$#" echo "arguments in reverse order:

write a non recursive shell script that accepts any number
of arguments and prints them in the reverse order

Question Posted / naresh babu

Answer Posted / naresh babu

echo "no of arguments:$#"
echo "arguments in reverse order:"
for i in $*
do
j=$i" "$j
done
echo $j

Is This Answer Correct ?

26 Yes

9 No

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