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The three boxes 1,2,3 has values resp. AB,BC,AC Get 2A(B+C)
+AC-2C(A-B)in Box 1 using only addition in 3 steps.
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Answer / ishant kshirsagar
GIVEN: 2A(B+C)+AC-2C(A-B)
THEREFORE 2AB+2AC+AC-2AC+2BC
2AB+AC+2BC
2(AB+BC)+AC
LET b1=AB b2=BC b3=AC
STEP1: b1 = b1+b2
so b1 = AB+BC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AC
STEP 2: b3 = b1+b3
so b3 = AB+BC+AC
THEREFORE
NOW: b1 = AB+BC b2 = BC b3 = AB+BC+AC
STEP3:
NOW: b1 = b1+b3
so b1 = AB+BC+AB+BC+AC
=2(AB+BC)+ AC
AB BC AC
STEP1 AB+BC BC AC
STEP2 AC BC AB+BC+AC
STEP3 AB+BC+AB+BC+AC BC AB+BC+AC
i.e 2(AB+BC)+AC BC AB+BC+AC
| Is This Answer Correct ? | 12 Yes | 0 No |
Answer / ujik
Same as above but step 2 should be add box 1 to box 1. A
little pedantic but but I would deduct marks for not meeting
the requirements.
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / vinay upadhyay
2A(B+C)+AC-2C(A-B)
=2AB+2AC+AC+2AC+2BC
=2AB+2BC+AC
b1 b2 b3
AB BC AC
STEP1 b1=b1+b1+b2
b1 b2 b3
2AB+BC BC AC
STEP2 b2=b1+b2
b1 b2 b3
2AB+BC 2AB+2BC AC
STEP3 b3=b2+b3
b1 b2 b3
2AB+BC 2AB+2BC 2AB+2BC+AC
| Is This Answer Correct ? | 8 Yes | 6 No |
Answer / anjali singla
On Solving the equation 2A(B+C)+AC - 2C(A-B)
we get 2AB+ 2BC+ AC
Step 1 : add box 2 value to box 1.
Step 2 : multiply it by 2 .
Step 3 : Add box 3 value to it .
| Is This Answer Correct ? | 7 Yes | 7 No |
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