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Two pipes can fill a tank in 10 and 12 hours respectively
while third pipe will make the tank empty in 20 hours. If
all three pipes operate simultaneously, in how many hours
the tank will be filled ?

Answers were Sorted based on User's Feedback



Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / anjali singla

In one hour :

Tank Filled by A = 1/10
Tank Filled by B = 1/12
Tank Empty be C = 1/20

If three pipes are combined then tank filled in one hour =
1/10 + 1/12 - 1/20
= 2/15
2/15 of tanked filled in one hour.
So time taken to fill tank = 15/2 * 1
= 7.5 hours

Is This Answer Correct ?    98 Yes 16 No

Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / lovedp

1/10 + 1/12 -1/20 = 15/2 i.e 7.5 h means 7 h & 30 min

Is This Answer Correct ?    33 Yes 5 No

Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / sabarish

1/10 + 1/12 - 1/20

solving we get... 7.5 hrs

Is This Answer Correct ?    28 Yes 9 No

Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / soumitra pandey

7.5hrs

Is This Answer Correct ?    11 Yes 8 No

Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / dhruv solanki

A=1/10
B=1/12
C=-1/20
Work in one hour= 1/10 + 1/12 - 1/20
= 2/15
Total Work = 15/2 hours or 7.5 hours or 7 hours 30 mins

Is This Answer Correct ?    1 Yes 4 No

Two pipes can fill a tank in 10 and 12 hours respectively while third pipe will make the tank empt..

Answer / ashwini

14 hours

Is This Answer Correct ?    4 Yes 36 No

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