a family has 4 people. father is 10kgs.mother 10
kgs.daughter 5 kgs,son 5 kgs........the family has to cross
a river to reach other side of land ..Assume they should go
from A to B....the boat is limited to carry 10 kgs at a
time...how will they reach?THERE IS NO SAILOR TO TAKE
THEM...
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FIRST TRIP:first two children go in boat to reach
destination B[10KGS]....one stays there -say son IS in B
RETURN :and other one daughter comes back with boat to A .
[weight of boat is 10kgs]
SECOND:then mother alone goes to reach
destination(B).....thus mother reached....[weight is 10
kgs]
RETURN :the other child son(in B) brings boat to the shore
A .....[5kgs]
THIRD:now both child travel to destination B...[10kgs]..one
child stays there say son
RETURN:and other one daughter brings boat back to A..[5kgs]
FOURTH:now father alone goes from A to B...[10kgs]therefore
father reached....
RETURN:the child ie,son in B comes to A [5kgs]
FIFTH:and takes other child daughter to B[10kgs]
| Is This Answer Correct ? | 31 Yes | 2 No |
Answer / v.manigandan.
first the son & daughter will go to the side B, from there
son will come to side A, then the father will goes to side B
and daughter will come to side A.again the son & daughter
will goes to side B and the son alone return to side A, then
the mother will goes to side B and the son will be there in
side A, when mom reaches the side B the daughter will come
to side to pick up the son, finally all will reach the side
B with out exceeding Weight 10 kgs.
| Is This Answer Correct ? | 16 Yes | 0 No |
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