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How to generate 3 digit random number?
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Answer / nazeer ahmed
dim upperlimit
dim lowerlimit
dim randomnumber(4)
upperlimit = 500
lowerlimit = 1
For x = 0 to 4
randomize timer
randomnumber(x)=Int((upperlimit-lowerlimit+1)*Rnd)+lowerlimit
msgbox randomnumber(x)
Next
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / prathyusha
Randomize
intmax=1000
intmin=300
rNum=Int((intmax-intmin+1)*Rnd+intmin)
MsgBox rnum
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / eswar
For i=1 to 3
x = RandomNumber(1,9)
y=y&x
Next
MsgBox y
| Is This Answer Correct ? | 0 Yes | 1 No |
Hi I don't have any idea on VBscript. can any one point me to a good web site to learn VBscript. Regards lina
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