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How to generate 3 digit random number?
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Answer Posted / nazeer ahmed
dim upperlimit
dim lowerlimit
dim randomnumber(4)
upperlimit = 500
lowerlimit = 1
For x = 0 to 4
randomize timer
randomnumber(x)=Int((upperlimit-lowerlimit+1)*Rnd)+lowerlimit
msgbox randomnumber(x)
Next
| Is This Answer Correct ? | 4 Yes | 2 No |
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