Answer / guest

Answer: D

Answer / subramani

D.) 10.1.1.127

No of valued hosts is
2^6-2=64-2=62

Therefore subnets are 0,64,128,256
since third subnet starts with 128,
127 will become the broadcast address for the second subnet
which is starting from 64.

Which network mask should you place on a Class C address to accommodate a user requirement of two subnetworks with a maxximum of 35 hosts on each networks A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248

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