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what is the value of b
if a=5;
b=++a + ++a
- 31 Answers
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Answer / sagar
here in b=++a + ++a;
a
Initial Value 5
First Prefix 6
Second Prefix 7
Final Equation b = 7 + 7 = 14...
So,correct answer is 14....
if the equation was as below:
c=++a;//a==6
d=++a;//a=7
b=c+d;//b=6+7=13
then b==13...
| Is This Answer Correct ? | 97 Yes | 29 No |
Answer / madhu cherukuri
a=5
b=++a +++a;
ANS:14
in this case the data will be storing in CPU register so the
result is 14 only.
volatile int a=5;
b=++a + ++a;
ANS:13
the data will be stored in directly memory
| Is This Answer Correct ? | 33 Yes | 15 No |
Answer / naresh
Not a very tough question. Important thing to note that in
any expression pre increment operator has a higher prority
than arithemetic operator as a result value of a is
increment is first two times then value of b is evaluated.
So b = 7*7 = 14.
in first ++a we get a=6
in next ++a we get a=7
and b=7+7=14
This question will result in same output for most of the
compilers, but some rare compiler may produce an entire
diffrenent parse tree resulting in an undefined result
| Is This Answer Correct ? | 28 Yes | 13 No |
Answer / anup dixit
13 is the correct answers. I'm attaching here a small java
program which proves this:
The program is:
------------------------------------------------------------
public class TestAddition
{
public static void main(String[] args)
{
int a=5;
System.out.println("1..Before a was : "+a);
int b = ++a + ++a;
System.out.println("Final a was : "+a+ ", int b =
++a + ++a is: "+b);
a=5;
System.out.println("2..Before a was : "+a);
int c= ++a+(++a);
System.out.println("Final a was : "+a+", int c=
++a+(++a) is: "+c);
}
}
------------------------------------------------------------
The output is:
------------------------------------------------------------
1..Before a was : 5
Final a was : 7, int b = ++a + ++a is: 13
2..Before a was : 5
Final a was : 7, int c= ++a+(++a) is: 13
| Is This Answer Correct ? | 15 Yes | 10 No |
Answer / kaps
IT is defenetly 14...Ans = 14
Explanation:
Because ++a = 6
then again ++a = 7
Now compiler replace the both value with 7 (because of both
are of value of a).
So 7+7 = 14.
It is tested on turbo C...
try with adding one more ++a will give u ans 24(8+8+8) for
++a + ++a + ++a.
| Is This Answer Correct ? | 8 Yes | 3 No |
How to add two numbers without using arithmetic operators?
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