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a=5
a=a++/++a
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Answer / prasannanjaneyulu.kandimalla
a=5;
a=a++/++a;
in that numerator is 5 and denominator is 6(finally a value
is:6)
so a=6/6=1
finally a is postincremented so it is2(1+1)
| Is This Answer Correct ? | 17 Yes | 4 No |
Answer / harinath
as the above person said the answer is right but
at first the evaluation starts from denominator, according
to operator precedence pre-increment has more value than
other two(/ and post-increment)
so at first ++a=6 is assigned to a
now the value in a is 6 .so 6/6 gives the value 1.
then post-increment occurs to the value in a(ie.,1).
so the value of a is finally 2(1+1).
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / svs
2
5=5++/++5
6=6++/6
6=6/6
6=1+increments one
answer is two
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / ajeet kumar
Ans a=2.
here a=a++/++a; //initial value of a=5.
1)firstly a=a++/++a <---it is pre-increment so firstly this
value will update.i.e a will be 6.
a=a++/6; //a=6
a=6/6; a=1;//after this line executions one increment will left of variable a.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / ss
answer can be 2 and 1 as well
actually it is compiler dependent
| Is This Answer Correct ? | 0 Yes | 4 No |
change to postfix a/(b+c*d-e)
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