Answer Posted / harinath

as the above person said the answer is right but
at first the evaluation starts from denominator, according
to operator precedence pre-increment has more value than
other two(/ and post-increment)
so at first ++a=6 is assigned to a
now the value in a is 6 .so 6/6 gives the value 1.
then post-increment occurs to the value in a(ie.,1).
so the value of a is finally 2(1+1).

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