Write a program to get the binary tree.
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Answer / r.r.bharti
Simple way:
public int FindDepthOfTree(RBNode n)
{
if (n == null) return 0;
return Math.Max(FindDepthOfTree(n.LeftNode),
FindDepthOfTree(n.RightNode)) + 1;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vamshi koduri
#include<iostream>
using namespace std;
typedef struct node
{
int d;
struct node *l,*r;
}node;
class bt
{
public:
int h,lev;
node *root;
node *create();
int height(node *);
void printlevel(node *,int lev);
void givenlevel();
void inorder(node *);
void preorder(node *);
void postorder(node *);
}a;
node *bt::create()
{
struct node *n;
n=new node;
int x;
cout<<"enter element
";
cin>>x;
if(x==-1)
return NULL;
n->d=x;
n->l=n->r=NULL;
cout<<"enter left "<<n->d<<ends;
n->l=create();
cout<<"enter right "<<n->d<<ends;
n->r=create();
return n;
}
void bt::inorder(node *p)
{
if(p!=NULL)
{
inorder(p->l);
cout<<p->d<<ends;
inorder(p->r);
}
}
void bt::preorder(node *q)
{
if(q!=NULL)
{
cout<<q->d<<ends;
preorder(q->l);
preorder(q->r);
}
}
void bt::postorder(node *q)
{
if(q!=NULL)
{
postorder(q->l);
postorder(q->r);
cout<<q->d<<ends;
}
}
int main()
{
a.root=a.create();
cout<<"levelorder: ";
a.givenlevel();
cout<<endl;
cout<<"inorder : ";
a.inorder(a.root);
cout<<endl;
cout<<"preorder : ";
a.preorder(a.root);
cout<<endl;
cout<<"postorder : ";
a.postorder(a.root);
cout<<endl<<"height: ";
cout<<a.height(a.root);
return 0;
}
int bt::height(node *p)
{
if(p==NULL)
return 0;
int l=height(p->l);
int r=height(p->r);
if(l>r)
h=1+l;
else
h=1+r;
return h;
}
void bt::givenlevel()
{
int p=height(root);
for(int i=1;i<=h;i++)
printlevel(root,i);
}
void bt::printlevel(node *p,int lev)
{
if(p==NULL)
return;
if(lev==1)
cout<<p->d<<ends;
if(lev>1)
{
printlevel(p->l,lev-1);
printlevel(p->r,lev-1);
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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#include <stdio.h> #include <alloc.h> #include <stdlib.h> #include <conio.h> void insert(struct btreenode **, int); void inorder(struct btreenode *); struct btreenode { struct btreenode *leftchild; struct btreenode *rightchild; int data; }; main() { struct btreenode *bt; bt=(struct btreenode *)NULL; int req,i=1,num; clrscr(); printf("Enter number of nodes"); scanf("%d",&req); while(i<=req) { printf("Enter element"); scanf("%d",&num); insert(&bt,num); i++; } inorder(bt); } void insert(struct btreenode **sr, int num) { if(*sr==NULL) { *sr=(struct btreenode *)malloc (sizeof(struct btreenode)); (*sr)->leftchild=(struct btreenode *)NULL; (*sr)->rightchild=(struct btreenode *)NULL; (*sr)->data=num; return; } else { if(num < (*sr)->data) insert(&(*sr)->leftchild,num); else insert(&(*sr)->rightchild,num); } return; } void inorder(struct btreenode *sr) { if(sr!=(struct btreenode *)NULL) { inorder(sr->leftchild); printf("\n %d",sr->data); inorder(sr->rightchild); } else return; } please Modify the given program and add two methods for post order and pre order traversals.
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