Child cObj = new Parent()
Wahts the output ?
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Answer / bhavin pandya
It will give yo Error :-
Object reference not set to an instance of an object.
If you want to create object then
Child cObj = new Child()
this is the right way
| Is This Answer Correct ? | 8 Yes | 3 No |
Answer / austin j seelan
Child cObj = new Parent()
This will through the compiletime error.
but we can create an instance like the foll.way
parent objparent = new child()
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / bangarraju
This is the DownCasting,but using like this
Child* obj=down_cast<Child* >(Parent) either using RTTI
mechanism in C++
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / donga bangarraju
sorry for the earlier post, this output is giving error like
initializing cannot convert to Paretn* to Child*, if u want
correct this code write like this, this is downcasting or
using RTTI mechanism in C++;
Parent* p =new Child;
Child* obj= dynamic_cast<Child*>(p);
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / aditya
Its java syntax where there is no pointers.
So its dynamic method dispatch which is same as virtual
functions of c++.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / chetan
it will execute without an error. if Parent class is
parent/base class and child is the child/drive class which
inherit parent class.
In the other worlds you are invoking drive class method with
the reference of base class.
| Is This Answer Correct ? | 3 Yes | 3 No |
Answer / giri
You can write below ways [Upcasting].
Child *cObj = new Parent();
| Is This Answer Correct ? | 5 Yes | 10 No |
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#include <iostream> using namespace std; struct wow { int x; }; int main() { wow a; a.x = 22; int c = a.x; int *b = new int; cout << c; return 0; } option: No output 0 22 -(11) Will not compile
#include <stdio.h> #include <alloc.h> #include <stdlib.h> #include <conio.h> void insert(struct btreenode **, int); void inorder(struct btreenode *); struct btreenode { struct btreenode *leftchild; struct btreenode *rightchild; int data; }; main() { struct btreenode *bt; bt=(struct btreenode *)NULL; int req,i=1,num; clrscr(); printf("Enter number of nodes"); scanf("%d",&req); while(i<=req) { printf("Enter element"); scanf("%d",&num); insert(&bt,num); i++; } inorder(bt); } void insert(struct btreenode **sr, int num) { if(*sr==NULL) { *sr=(struct btreenode *)malloc (sizeof(struct btreenode)); (*sr)->leftchild=(struct btreenode *)NULL; (*sr)->rightchild=(struct btreenode *)NULL; (*sr)->data=num; return; } else { if(num < (*sr)->data) insert(&(*sr)->leftchild,num); else insert(&(*sr)->rightchild,num); } return; } void inorder(struct btreenode *sr) { if(sr!=(struct btreenode *)NULL) { inorder(sr->leftchild); printf("\n %d",sr->data); inorder(sr->rightchild); } else return; } please Modify the given program and add two methods for post order and pre order traversals.
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