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suppose A is a base class and B is the derved class. Both
have a method foo which is defined as a virtual method in
the base class. You have a pointer of classs B and you
typecast it to A. Now when you call pointer->foo, which
method gets called?
The next part of the question is, how does the compiler
know which method to call?
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Answer / nm
The answer is that B->foo gets calle, and why ? I found a
good explanation of that here:
http://en.wikipedia.org/wiki/Virtual_table
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / rahul
the answer is that compiler does only the the type checking at compile time it checks only that the type of reference or the type of object is being assigned to the type is assignable or not(i.e parent child relationship or cast operation should be valid otherwise it will give you compile time error) and compiler conveys the message to the runtime that this operation is valid so no type checking is done at run time, at runtime function call depends upon the actual object being referred by the type but the existance of that function is checked in the type class if the function doesn't exist in the type class the function will not be called even though it exist in the class which is being instantiated by type(reference type)
for example A a = new B();
a.foo();
here we are calling the foo() method of class B(because object of class B is being instantiated)using class A reference now here when we compile this program the compiler checks for foo() method in class A if this method doesn't exist in class A compiler even will not compile your program
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / suchi
It depends the pointer points to the object of which class.
If the pointer points to Class A, then the method defined
in class A will be called, and if the pointer points to
class B, then the method defined in class B will be called.
| Is This Answer Correct ? | 2 Yes | 6 No |
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