Answer / jitendra kumar sinha

hi Arif
As you know that route slection is depend upon the AD value
now
acording to the your question your roting table conatin
static rip and eigrp

so deaqfult value of these routing protocol is
eigrp have ad value of 90
rip have the ad value of 120
static have the AD value of 1

so static is the Answer for your questions

Answer / dharmendra kumar soni

hello friends,


This is right answer static for your question because as
we know that all routing protocol which has AD value and
find the route on the basis.

Answer / jitu bhia

Thanks shain for your support in my favor i was litle it
confused after seeing there answer

Thanks again


tell me why this question ask when ever i ma going to
provide any answer

the questions is

6 + 3 = ?

Answer / okesade o a

Yes,staic route would be make use by the routiing table
becouse the default AD is 1 except there is a change done
by the Network Amin

Answer / harindra

static is correct because of low AD value

Answer / ratnadeepak.b

U r right vivek.. it's Autonomous System Number, and the
answer is Static route.

Answer / shahin

Hello Guys, if i m not wrong, thn Jitu is correct.... As far
as my concern, AD value is used in the route selection
process, not AS value...!!!

So Mr.Vivek, Cud u explain how AS value influence in route
selection process???????? I will be thankful to u if u
explain it..!!!

Answer / vijay

here it uses static route..
bcz the default administrative value of
static is 0
rip is 120
eigrp is 90 &
ospf is 110

then least admin value has high priority.
there fore static route is used

Answer / shahin

Hey Guys... stop answering answered question.....!!! Lots of
unanswered questions are there.. try those once...!!!! Its a
humble request...!!!

Answer / rick

Forwarding decision will always first depend upon Longest Prefix Match Rule.
If you have have a routing table as follows:
+-----------------------------------------------------------------------------+
+ S 192.168.0.0/16 [1/0] via fast Ethernet 0/0 +
+ D 192.168.1.0/24 [90/*] via fast Ethernet 0/0 +
+ O 192.168.1.1/32 [110/*] via fast Ethernet 0/0 +
+-----------------------------------------------------------------------------+

And now if you ping 192.168.1.1, then according to longest prefix match rule it will take path via OSPF learned route.

If this path goes down, again longest prefix match rule come in action, and the path learned via EIGRP will be used.

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