Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks

Hi, Anybody could tell me What is the 3rd Largest Number in
the series..Thanks in Advance..

Question Posted / gardasulaxmi

3 Answers
6409 Views
Amazon, bcbs, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / saket bharti

a=Array(-1,0,23,-12,98,-300)

Dim temp,i,j

For j=0 to UBound(a)-1

For i=0 to UBound(a)-1

If a(i)<a(i+1) then

temp=a(i+1)

a(i+1)=a(i)

a(i)=temp

End If

Next

Next

Msgbox a(2)

Is This Answer Correct ?

4 Yes

1 No

Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / pushkar1206

a=array(1,22,3,40,12)
For i=0 to ubound(a)
For j=0 to ubound(a)
If a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
Next
Next
print a(2)

Is This Answer Correct ?

1 Yes

0 No

Hi, Anybody could tell me What is the 3rd Largest Number in the series..Thanks in Advance....

Answer / anwar basha

dim temp,i,j
a=array(5,3,7,9,2,...)

for i=0 to ubound(a)-1
for j=i+1 to ubound(a)
if a(i)>a(j) then
temp=a(i)
a(i)=a(j)
a(j)=temp
end if
next
next
k=ubound(a)-2
msgbox a(k)

Is This Answer Correct ?

0 Yes

0 No

Post New Answer