How to get the 3rd column(i.e all the data along with the column name)in a table?2 5450
type type_name is table of varchar2(30) index by binary_integer for the above type you have to create a identifier... like identifier_name type_name; for the above type you can use the below methods..like first , last , prior, next , delege..etc...like this.. if you create a cursor...like cursor cursor_name is select * from scott.emp; is there any methods like above to use prior, fist , last , next , trim ,etc...1 4598
what is the difference between varray and table data type..please expalain with some examples... under what situation you will go for varray..instead of index by table...1 1441
declare v_count number(8,3); v_sal scott.emp.sal%type := '&P_sal'; cursor cur_name is select sal from scott.emp where sal between (v_sal-100) and (v_sal +1000); begin v_count :=nvl(sql%rowcount ,0); if v_count = 0 then dbms_output.put_line('no records are fetch in the given sal range'); else dbms_output.put_line('There is/are '||to_char(v_count)|| ' salaries are selected in the given range '); end if; end; in the above programm .....for any sal range ....always it shows the following message.. no records are fetch in the given sal range please find the mistake and share with me...with thansk and regards..sarao....3 4225
1. is it possible to use the cursor atttibutes (%found ,% rowcount , %isopen , %notfound ) to our user defined cursor names ....... cursor cursor_name is select * from scott.emp if you use... cursor_name%found , %rowcount ,%isopen,%notfound...will it work... -------------------------- 2.what is the difference between the varray and index by table .. -------- 3. type type_name is table of number(8,3) index by binary_integer; identifier_name type_name; first , last , prior , next ,trim are the methods we can use it for the above type...simillary is there any way to apply for cursors... with thanks and regards..sarao...981
suppose I have two table one Emp and other is dpt. Emp table has a field ,dept id,name ,sal and dpt table has a field dept id,dept name. Now I want to find out the emplyee list whose sal is between 2000-3000 from dept x.7 6929
1.when will you use week refcursor and when will you use strong ref cursor ? 2.what is the use of sql trace..how do you use it ? 3.can you please send all the sql plus commands...like set line 6000....1 3359
1. how to use the check option constraints in sql query..? 2.how to add data in a complex query ? 3.is it possible to use commit or rollback or savepoint in triggers...if not why please explain with examples...? 4.what is the difference between meterialized view and normal view..how to create materialized view and how to use it..? 5.what is varray...? what is the advantage of the varray ? please expalin with a simpel example..i want to load into a table (student no and name and his marks..) please give example.. 6.what are the bulk bind exceptions...how to use bulk bind and how to use bulk collect..please explain with example... 7.what is for update of and where current of ...? 8 what is the use of nowait ? 9.please give an example for nocopy in a simple plsql query 10.create an index in a table...tellme how to use the index in a where clause to do performance tunning...3 5421
define primary key & secondary key?2 14666
Write a query to find second highest salary of an employee.26 11934
What are the different types of joins and explain them briefly.3 8039
what is the output of this query selet * from employee where 1=2 ??11 9746
hello..... i am an comp science engineering graduate planning to do ORACLE certification in PLSQL 9i. just wanted to know whats the possibility getting job is their openings???? is it worth doin that course n certification715
Hi am new to PLSQL & facing problems in writing code like in SP, Functions, so any one having some SP coding with in depth explanation please share with me my Email ID firstname.lastname@example.org Or taking tanning on this please do contact me
Whis is not false in primary key?
create SQL (both DML/DDL) statements appropriate for the creation of relational structures & constraints and other objects for a given case study, the population of these tables and the manipulation (querying/updating) of the stored data. 2. Create, develop and use the PL / SQL Program Units Procedures, Functions as a progression towards Object Oriented Relational Database Programming. 3. Package a collection of logically related Procedures and Functions together to further move towards development of Objects which reflect the principle of Data Abstraction whereby only an Object specified in the Interface is accessible to the end user. 4. Select, create, and use appropriate Database Triggers to impose agreed specific constraints on a Database Table. 5. Provide a full and detailed evaluation which includes a comprehensive test execution plan and its implementation for each of the above. Consider the following case study: Perilous Printing is a medium size printing company that does work for book publishers throughout UK. The company currently has 10 offices, most of which operate autonomously, apart from salaries, which are paid by the head office. Currently the sharing and communication of data, is carried out using multi- user networked access to a centralised RDBMS. Perilous Printing jobs consist of printing books or part of books. A printing job requires the use of materials, such as paper and ink, which are assigned to a job via purchase orders. Each printing job may have several purchase orders assigned to it. Likewise, each purchase order may contain several purchase order items. The following tables form part of the transactional RDB that the company uses: office (office_no, o_addr, o_telno, o_faxno, mgr_nin) staff (staff_no, nin, fname, lname, s_addr, s_telno, gender, dob, position, taxcode, salary, office_no) publisher (pub_no, p_name, p_city, p_telno, p_faxno, credit_code, office_no) book_job (job_no, pub_no, job_date, job_desc, job_type, job_status, supervisor_nin) purchase_order (job_no, po_no, po_date) po_item (job_no, po_no, it_no, qty) item (it_no, it_desc, amt_in_stock, price) office contains details of each office and the office number (office_no) is the key. Each office has a Manager represented by the manager’s national insurance number (mgr_nin). staff contains details of staff; the staff_no is the key. The office that the member of staff works from is given by office_no. publisher contains details of publisher and the publisher number (pub_no) is the key. Publishers are registered with the nearest office in their country, given by office_no, and they are given a credit code that can have the values “AA”, “AB”, “BB”, “BC”, “CC”, “CD” and “DD”. If a publisher is to be deleted then not only the publisher’s entry from the publisher table will have to be removed but all the data associated with the particular supplier has to be deleted too book_job contains details of publishing jobs and the job number (job_no) is the key. The publisher is given by the publisher number (pub_no) and the supervisor for the job by supervisor_nin. The job type can be either null or urgent; whereas the job_status can be “ongoing” or “completed” purchase_order contains details of the purchase orders for each job and the combination of job number and a purchase order number (job_no, po_no) form the key. Each printing job may have several purchase orders assigned to it. item contains details of all materials that can be used in printing jobs and the item number (it_no) is the key. po_item contains details of the items on the purchase order and (job_no, po_no, it_no) forms the key. In the above given database schema, descriptions are strings of characters (at most 30 characters long), any dates (except the job_ date) stored cannot be after the current system date, and quantities and prices are assumed to be non-negative numbers.
C. Normalize the following data up to the 3rd Normal form. Create the tables and insert the data given. Emp_ID Name Dept_Name Salary Course_Title Date_Completed 100 Adam Marketing 48,000 SPSS 6/19/2008 Surveys 10/7/2008 140 Bob Accounting 52,000 Tax Acc 12/8/2008 110 Cathy IT SQL Server 1/12/2008 C# 4/22/2008 190 Dan Finance 150 Emily Marketing 55,000 SPSS 6/16/2008 42,000 Analysis 8/12/2008 Queries 1. Find all Names who have completed the SPSS Course. 2. Find employee with max salary. 3. Find employee with 2nd max salary. 4. Find all employees in Dept “Marketing”. 5. Find all the employees who have taken more than 2 courses. 6. Find all the employees who have completed the courses before month of September.
What will be the output of the following String S = 1+2+"abc" S = ? String S1 = 1+2+"abc"+5+6 S1 = ?
ERROR:Insert or update on table"accnt" violates foreign key constraints "acct_to_curr_symbol" DETAILS:KEY(accnt_curr_id)(-2)is not present in the table "curr_symbol" ......solve The Problem..
What is Materialized View? In What Scenario we Use Materialized View?
What are code pages ?
Could you please provide oca (oracle 10g) dumps for my certification ?
what is single byte over head in oracle..?
What packages(if any) has oracle provided for use by developers?
hi,i plan to put experience on PLSQL ,can anyone suggest me for any institutes in bangalore or how to prepare for interviews
What is your daily office routine?
How to generate a salary slip like jan 1000 1000 feb 1000 2000 ... dec 1000 12000
Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin