What action do you have to perform before retrieving data from the next result set of a stored procedure ?
What are code pages ?
How consistent is the view of the data between and within multiple sessions, transactions or statements ?
what is the bond code in materialized view?
when MSQL8.0 is in market
Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin
If i can use sys.check_constraints to display my constraints from my database using sql server 2005, how can i display then if i am using sql server 2000????
GLOBAL TEMPORARY TABLE over Views in advantages insolving mutating error?
what is the use of anchoring object? what r the difference between anchoring object & enclosing object? can any one tell me all the details?
a table has 2 classifications 1)liabilities 2)earnings this liabitity has 2 elements with 2 input values and the earnings have 2 elements with 2 input values i wrote a query so that my input is liability savings amount1 amount2 xxxx null xxxxxx 0 xxx1 null xxxxx1 0 null yyyy 0 yyyy null yyy1 0 yyy1 my problem is --when i developed a report(d2k) with this data my o/p is liabilities,amount1,savings,amount2 xxxx xxxxxx xxx1 xxxxx1 yyyy yyyy yyy1 yyy1 how could i move this savings,savings values 2 palces up. can any body provide me witha better solution
C. Normalize the following data up to the 3rd Normal form. Create the tables and insert the data given. Emp_ID Name Dept_Name Salary Course_Title Date_Completed 100 Adam Marketing 48,000 SPSS 6/19/2008 Surveys 10/7/2008 140 Bob Accounting 52,000 Tax Acc 12/8/2008 110 Cathy IT SQL Server 1/12/2008 C# 4/22/2008 190 Dan Finance 150 Emily Marketing 55,000 SPSS 6/16/2008 42,000 Analysis 8/12/2008 Queries 1. Find all Names who have completed the SPSS Course. 2. Find employee with max salary. 3. Find employee with 2nd max salary. 4. Find all employees in Dept “Marketing”. 5. Find all the employees who have taken more than 2 courses. 6. Find all the employees who have completed the courses before month of September.
1. is it possible to use the cursor atttibutes (%found ,% rowcount , %isopen , %notfound ) to our user defined cursor names ....... cursor cursor_name is select * from scott.emp if you use... cursor_name%found , %rowcount ,%isopen,%notfound...will it work... -------------------------- 2.what is the difference between the varray and index by table .. -------- 3. type type_name is table of number(8,3) index by binary_integer; identifier_name type_name; first , last , prior , next ,trim are the methods we can use it for the above type...simillary is there any way to apply for cursors... with thanks and regards..sarao...
what is single byte over head in oracle..?
create SQL (both DML/DDL) statements appropriate for the creation of relational structures & constraints and other objects for a given case study, the population of these tables and the manipulation (querying/updating) of the stored data. 2. Create, develop and use the PL / SQL Program Units Procedures, Functions as a progression towards Object Oriented Relational Database Programming. 3. Package a collection of logically related Procedures and Functions together to further move towards development of Objects which reflect the principle of Data Abstraction whereby only an Object specified in the Interface is accessible to the end user. 4. Select, create, and use appropriate Database Triggers to impose agreed specific constraints on a Database Table. 5. Provide a full and detailed evaluation which includes a comprehensive test execution plan and its implementation for each of the above. Consider the following case study: Perilous Printing is a medium size printing company that does work for book publishers throughout UK. The company currently has 10 offices, most of which operate autonomously, apart from salaries, which are paid by the head office. Currently the sharing and communication of data, is carried out using multi- user networked access to a centralised RDBMS. Perilous Printing jobs consist of printing books or part of books. A printing job requires the use of materials, such as paper and ink, which are assigned to a job via purchase orders. Each printing job may have several purchase orders assigned to it. Likewise, each purchase order may contain several purchase order items. The following tables form part of the transactional RDB that the company uses: office (office_no, o_addr, o_telno, o_faxno, mgr_nin) staff (staff_no, nin, fname, lname, s_addr, s_telno, gender, dob, position, taxcode, salary, office_no) publisher (pub_no, p_name, p_city, p_telno, p_faxno, credit_code, office_no) book_job (job_no, pub_no, job_date, job_desc, job_type, job_status, supervisor_nin) purchase_order (job_no, po_no, po_date) po_item (job_no, po_no, it_no, qty) item (it_no, it_desc, amt_in_stock, price) office contains details of each office and the office number (office_no) is the key. Each office has a Manager represented by the manager’s national insurance number (mgr_nin). staff contains details of staff; the staff_no is the key. The office that the member of staff works from is given by office_no. publisher contains details of publisher and the publisher number (pub_no) is the key. Publishers are registered with the nearest office in their country, given by office_no, and they are given a credit code that can have the values “AA”, “AB”, “BB”, “BC”, “CC”, “CD” and “DD”. If a publisher is to be deleted then not only the publisher’s entry from the publisher table will have to be removed but all the data associated with the particular supplier has to be deleted too book_job contains details of publishing jobs and the job number (job_no) is the key. The publisher is given by the publisher number (pub_no) and the supervisor for the job by supervisor_nin. The job type can be either null or urgent; whereas the job_status can be “ongoing” or “completed” purchase_order contains details of the purchase orders for each job and the combination of job number and a purchase order number (job_no, po_no) form the key. Each printing job may have several purchase orders assigned to it. item contains details of all materials that can be used in printing jobs and the item number (it_no) is the key. po_item contains details of the items on the purchase order and (job_no, po_no, it_no) forms the key. In the above given database schema, descriptions are strings of characters (at most 30 characters long), any dates (except the job_ date) stored cannot be after the current system date, and quantities and prices are assumed to be non-negative numbers.
how to delete duplicate rows from a join tables(I have three tables on that join) how do you know which join is need to be used? The select statement I have is: SELECT gc_skill_type.skill_type, gc_area_tec.area, gc_technology.technology, gc_technology.id_technology, gc_area_tec.id_area_tec FROM gc_skill_type, gc_area_tec, gc_technology WHERE gc_area_tec.id_skill_type (+) = gc_skill_type.id_skill_type AND gc_technology.id_area_tec (+) = gc_area_tec.id_area_tec order by gc_skill_type.skill_type asc, gc_area_tec.area asc, gc_technology.technology asc