main() {int a=200*200/100; printf("%d",a); }

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main()
{int a=200*200/100;
printf("%d",a);
}

Question Posted / amir

14 Answers
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main() {int a=200*200/100; printf("%d",a); }..

Answer / vishi

200*200=40000;
as the range of int(-32768 to +32767)
40000 exeeds +32767 &hence goes to the other side,
40000-32767=7233;
now (-32768+7233)=(-25535);
hence the value of 40000 will be -25535;
result be (-25535/100)="-255"(integer value).

Is This Answer Correct ?

24 Yes

2 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / vignesh1988i

output is : 400

Is This Answer Correct ?

36 Yes

18 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / pravin

Is This Answer Correct ?

26 Yes

10 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / deepak roniya

explanation 7 is right......i also run this program and the
result is -255

Is This Answer Correct ?

10 Yes

1 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / sreepal

-255

Is This Answer Correct ?

5 Yes

1 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / vivek shah

because
int range 32767 to -32768
200*200=4000;
so out of range

-255

Is This Answer Correct ?

2 Yes

0 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / tanvi jain

Is This Answer Correct ?

0 Yes

0 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / shafi

int a=200*200/100;/*it is related with assignment operator so
it's right->left shift*/
=200*2;
=400;
the value of a=400

Is This Answer Correct ?

0 Yes

0 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / xxxxxxx

among '* ','/' arithematic operators / has a higher
precedence.so 200/100 is enclosed in brackets and multiplied
with 200
so a=200*(200/100)=200*2=400

Is This Answer Correct ?

0 Yes

1 No

main() {int a=200*200/100; printf("%d",a); }..

Answer / pawan singh

400

Is This Answer Correct ?

12 Yes

14 No

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