Answer / saurabh

it is a example of overloading:-
class Overload {
void test(int a) {
System.out.println("a: " + a);
}
void test(int a, int b) {
System.out.println("a and b: " + a + "," + b);
}
double test(double a) {
System.out.println("double a: " + a);
return a*a;
}
}
class MethodOverloading {
public static void main(String args[]) {
Overload overload = new Overload();
double result;
overload.test(10);
overload.test(10, 20);
result = overload.test(5.5);
System.out.println("Result : " + result);
}
}

Answer / binod kumar

IF WE HAVE SAME METHOD NAME WITH DIFFERENT TYPES OF PARAMETERS THEN IT IS KNOWN AS METHOD OVERLOADING.
EXAMPLE----------->

class A
{
void sum(int a,int b)

{
int s=a+b;
System.out.println("Sum of a+b is:" +s);

}
void sum(int x,int y,int z)
{
int s2=x+y+z;
System.out.println("Sum of x+y+z is:" +s2);

}
}

class ovrloading
{

public static void main(String str[])

{
A a=new A();
a.sum(10,20);
a.sum(10,20,30);
}
}
IN GIVEN EXAMPLE WE HAVE SUM METHOD WITH DIFF PARAMETERS.
OUTOUT WILL BE------->
Sum of a+b is: 30
Sum of x+y+z is: 60

Answer / sagar

i think partial operator overloading is possible in java

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