#include<stdio.h>
int main()
{ int i=0,j=1,k=2,m,n=0;
m=i++&&j++&&k++||n++;
printf("%d,%d,%d,%d,%d",i,j,k,m,n);
}
Answers were Sorted based on User's Feedback
Answer / g krishna rao
1,1,2,0,1
when it encounters zero it will not check remaining conditions
and go to or conditions and incriment n
Is This Answer Correct ? | 3 Yes | 2 No |
Answer / manish soni tagore collage jai
m=i++&&j++&&k++||n++;
in this expression
first
m=0++&&...........
from rule of && opr c1&&c2
if c1 is 0(FLASE) it don't chacke the next expression
so
m=0---------------(1);
after this
m=i++&&j++&&k++||n++;
-----------------------
m=i++&&j++&&k++ is flase so only i is increase by and j and
k not effect.
-------------------------------
after that
in ||(OR )OPR
C1||C2
IF C1 IS 0(FALSE) THEN IT CHECK THE C2
m=i++&&j++&&k++(C1)||n++(C2);
THEN C1 IS 0 and c2 is 0++ is 1 so true.
so answer is
1,same,same,0,i,
Is This Answer Correct ? | 4 Yes | 4 No |
Answer / kishore krishnan.s.r
Its actually a doubt
Since ++ has high precidence than && will it not be evaluated first.
then ans will be 1,2,3,0,1
Is This Answer Correct ? | 0 Yes | 1 No |
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