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main()
{
void swap();
int x=10,y=8;
swap(&x,&y);
printf("x=%d y=%d",x,y);
}
void swap(int *a, int *b)
{
*a ^= *b, *b ^= *a, *a ^= *b;
}
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Answer Posted / susie
Answer :
x=10 y=8
Explanation:
Using ^ like this is a way to swap two variables without
using a temporary variable and that too in a single statement.
Inside main(), void swap(); means that swap is a function
that may take any number of arguments (not no arguments) and
returns nothing. So this doesn’t issue a compiler error by
the call swap(&x,&y); that has two arguments.
This convention is historically due to pre-ANSI style
(referred to as Kernighan and Ritchie style) style of
function declaration. In that style, the swap function will
be defined as follows,
void swap()
int *a, int *b
{
*a ^= *b, *b ^= *a, *a ^= *b;
}
where the arguments follow the (). So naturally the
declaration for swap will look like, void swap() which means
the swap can take any number of arguments.
| Is This Answer Correct ? | 4 Yes | 0 No |
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