Interested to Buy Any Domain ? << Click Here >> for more details...
A packet of 10 Kb is to be downloaded from a web server.
Find the time needed to download this packet using:
a) A dial up telephone connection at 28 Kbps
b) A cable modem at 28 Mbps.
- 5 Answers
- 9782 Views
- Ericsson, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / david tilley
The straight maths answer is: Ti = Fs/Sp
Where:
Ti...Time
Fs..FileSize
Sp..Speed
a) Ti = 10,000 / 28,000
= 357ms
b) Ti = 10,000/ 28,000,000
= 357uS
However.... In practice transfer times would be longer than
this depending on the overhead added to handle error
checking/recovery.
| Is This Answer Correct ? | 30 Yes | 6 No |
Answer / vaibhav
the correct answer is below
10kb=10*1024bytes=10240 bytes
28Kilobitsps=28/8KiloBytesps=3.5KBps=3.5*1024Bytesps=3584Bps
time=10240/3584=2.85 s
do same with 28.8Mbps=28.8*1024*1024.
| Is This Answer Correct ? | 7 Yes | 5 No |
Answer / john
I agree this is the correct one.
10kb=10*1024bytes=10240 bytes
28Kilobitsps=28/8KiloBytesps=3.5KBps=3.5*1024Bytesps=3584Bps
time=10240/3584=2.85 s
do same with 28.8Mbps=28.8*1024*1024.
| Is This Answer Correct ? | 2 Yes | 3 No |
How come the systems know to differentiate between network id and the host id?
How do I refresh my ip address?
How a process can be terminated?
What is the difference between a primary server and a secondary server?
Can the IP address same for 2 pcs?
In IP at which place the error control is done when a data is corrupted?
How do I check if a port is open?
Explain how do applications coexist over tcp and udp?
What is the protocol used in Network layer?
What port is 23?
what is the difference between server and database?
How to instal two operarting system in one pc?
SNMP 
