The straight maths answer is: Ti = Fs/Sp Where: Ti...Time Fs..FileSize

A packet of 10 Kb is to be downloaded from a web server.
Find the time needed to download this packet using:
a) A dial up telephone connection at 28 Kbps
b) A cable modem at 28 Mbps.

Question Posted / david tilley

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Answer Posted / david tilley

The straight maths answer is: Ti = Fs/Sp
Where:
Ti...Time
Fs..FileSize
Sp..Speed

a) Ti = 10,000 / 28,000
= 357ms
b) Ti = 10,000/ 28,000,000
= 357uS

However.... In practice transfer times would be longer than
this depending on the overhead added to handle error
checking/recovery.

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