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Write a C++ program without using any loop (if, for, while
etc) to print numbers from 1 to 100 and 100 to 1;
Answers were Sorted based on User's Feedback
Answer / harpreet kaur
we can create our own header file having a function to
print nos with loop and then use that header file in new
prog with the functoin defined in it.
| Is This Answer Correct ? | 30 Yes | 37 No |
Answer / ravi sagar
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i;
int j=100;
int c=0;
printf("1 to 100 then 99 to 1");
for(i=1;i<=100;i++;)
{ if (c==0)
{
printf("%d",i);
if(i==100)
{
c=1;
}
}
if(c==1)
{
j--;
printf("%d",j);
if(j==0)
{
break;
}
}
}
| Is This Answer Correct ? | 4 Yes | 11 No |
We can do that by recursive call.....
void fun(int no ){
int t;
printf("%d ",no);
if( no != 100 ){
t=no+1;
fun(t);
}
printf("%d ",no);
}
int main(){
fun(1);
return 0;
}
| Is This Answer Correct ? | 17 Yes | 27 No |
Answer / solairaja
void main()
{
int i;
V:
printf("%d",i++);
goto V;
}
| Is This Answer Correct ? | 3 Yes | 17 No |
Answer / pur
main()
{
int i =100;
start:
if( i == 0)
goto end;
printf(" %d ",i)
i--;
goto start;
end:
printf(" end of the program");
}
| Is This Answer Correct ? | 20 Yes | 47 No |
Answer / gandhi priyank
goto statment is also right because goto statement is not a
loop
e.g.
void main()
{
j:
printf("type your text here");
goto j;
}
| Is This Answer Correct ? | 10 Yes | 42 No |
Answer / balaji.k
#include<stdio.h>
#include<conio.h>
void main()
{
clescr();
int i,chl,start;
printf("enter the number from 1 to 100\n");
scanf("%d",ch);
else
go to start
start=1 to 100;
else
go end
exit(0);
}
| Is This Answer Correct ? | 3 Yes | 37 No |
Answer / govind
#include<conio.h>
#include<stdio.h>
void main()
{
int i;
clrscr();
printf("\n the value of the 100 to 0 \n");
for(i=100;i>0;i--)
{
if(i==0)
{
goto start;
}
printf(" %d\t",i);
}
printf("\nthe value of the 0 to 100 \n ");
start:
if(i==100)
{
goto end;
}
printf("%d\t",i);
i++;
goto start;
end :
printf("End of the program");
getch();
}
| Is This Answer Correct ? | 6 Yes | 67 No |
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