A circular road runs round a circular ground. If the
difference between the circumference of the outer circle
and inner circle is 44 meters, find the width of the road?
Answers were Sorted based on User's Feedback
Answer / suman
(2*PI*R)-(2*PI*r)=44
2*(22/7)(R-r)=44
R-r=(44*7)/44
Road width=(R-r)=7 meters
Is This Answer Correct ? | 13 Yes | 3 No |
Answer / santanu chakraborty
2#(r1-r2)=44
or, r1-r2=7
so the width is 7m
Is This Answer Correct ? | 9 Yes | 0 No |
Answer / priyanka thakare
2#r1-2#r2=44
2#(r1-r2)=44
r1-r2=44/2#
//here #=3.14//
r1-r2=7m
Is This Answer Correct ? | 4 Yes | 2 No |
Answer / srinivas panguluri
circumference of a circle = 2#r or #d
2#(r2-r1) = 44
r2-r1 = 44/2#
=14
Is This Answer Correct ? | 14 Yes | 18 No |
Answer / vignesh1988i
THE WIDTH OF THE ROAD IS 7.6meters.......
given that (2*3.14*r1)-(2*3.14*r)=44
2*3.14(r1-r)=44
r1-r=22/3.14
r1-r= 7.6m
thank u
Is This Answer Correct ? | 3 Yes | 13 No |
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