Answer / yuusaku

int num;
sscanf(string,"%x",&num);

Answer / john huang

int n=strlen(x) // where x is pointer to hex string
int sum=0;
int leftshift=0;
while(n>0)
{
if((x[n-1]>='0') && (x[n-1]<='9'))
sum+=(x[n-1]-'0')<<leftshift;
if((x[n-1]>='A') && (x[n-1]<='F'))
sum+=(x[n-1]-'A'+10)<<leftshift;
if((x[n-1]>='a') && (x[n-1]<='f'))
sum+=(x[n-1]-'a'+10)<<leftshift;
n--;
leftshift+=4;
}

Answer / mohammed sardar

int n=strlen(x) // where x is pointer to hex string
int sum=0;
int leftshift=0;
while(n>0)
{
if((x[n-1]>='0') && (x[n-1]<='9'))
sum+=(x[n-1]-'0')<<leftshift;
if((x[n-1]>='A') && (x[n-1]<='F'))
sum+=(x[n-1]-'A'+10)<<leftshift;
if((x[n-1]>='f') && (x[n-1]<='f'))
sum+=(x[n-1]-'a'+10)<<leftshift;
n--;
leftshift+=4;
}

Answer / vadivel t

Hi,
Refer below link to know how atoi() lib fuction works.
http://www.cppreference.com/wiki/c/string/atoi

And find the equalent code which i have written here.

#include<stdio.h>
#include<conio.h>

int MyAtoi(char *cptr);

main()
{
/*Give different inputs like "12.3432", "a4523"," 123"
"abcd", "1234f" and find the qualent output*/

char *cptr = "123445";

printf("INTEGER EQU IS: %d\n", MyAtoi(cptr));
getch();
}
int MyAtoi(char *cptr)
{
int iptr = 0;
while((*cptr != '\0') && ((*cptr >= 48 && *cptr <= 57) ||
(*cptr == 32)))
{
if(*cptr != ' ')
iptr = (iptr * 10) + (*cptr - 48);
cptr++;
}
return iptr;
}

Answer / audrius

long l = strtol(string, NULL, 16);
//or, if you need unsigned (which you usually do with hexes)
unsigned long ul = strtoul(string, NULL, 16);

please send me papers for Dy. manager IT , PNB. it would be a great help for me.

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