Take this question as challange --> "Candle 'A' takes just
four hours to burn it completely and candle 'B'
takes 2 hrs. The girth of candle 'A' is just double of
candle 'B' with the same height. If Ram lit both the
candles in the same time and after how long time the length
of Candle 'B' would be just half of candle 'A'?
Answers were Sorted based on User's Feedback
Answer / atul
If both candles are of height x.
Suppose both candles were burnt for t hrs.
First one can burn for 4 hrs.
First one can burn for x/4 in 1 hr.
First one can burn for t*x/4 in t hr.
Balance = (x-t*x/4)
second one can burn in 2 hrs.
second one can burn in x/2 in 1 hr
Second one can burn for t*x/2 in t hr.
Balance = (x-t*x/2)
as per given condition
Balance = (x-t*x/4) = 2*(x-t*x/2)
or
1-t/4 = 2-t
t-t/4 =1
3*t/4=1
so t= 4/3 hrs
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / sheeba manuel
Since both the candles are of the same height, and
candle B takes 2 hours to burn fully means, the time
taken for candle B to be just half of candle
A is 1 hour. (Half of candle A = half of candle B,
b'cos they have the same height)
Therefore answer is 1 hour
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / amar jeet singh
not possible because they are burnt at the same time
| Is This Answer Correct ? | 0 Yes | 6 No |
If A=Z, B=Y, C=X, .......... Z=A, Then GROUP = ?
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