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How to write a code for random pick from 1-1000 numbers?
The output should contain the 10 numbers from the range
1-1000 which should pick randomly, ie ,for each time we run
the code we should get different outputs.
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Answer / vignesh1988i
hi... guys... what i think is that we can make use of files... because it is asked that each time we run the code it must generate different numbers..... .. only in file it will be saved pernmently ....
first let us create a file to give a starting number to start the generation....
let us assume that we have created a file named random.txt... in that we have a number 21 (assumption)..
#include<stdio.h>
#include<conio.h>
void main()
{
FILE *pointer,*pointer1;
char ch;
int r=0,n[10],count=0;
pointer=fopen("random.txt","r");
while(1)
{
ch=fgetc(pointer);
if(ch==EOF)
break;
else
r=r+((ch-'0')*10); // to change char to int
}
int j=31;
for(int i=0;i<10;i++)
{
printf("%d",r+12+j);
if(i%2==0)
j+=42;
}
r+=23;
for(i=0;r>0;i++)
{
n[i]=r%10;
r=r/10;
}
pointer1=fopen("random.txt","w");
fflush(stdin);
i=0;
while(1)
{
count++;
ch=n[i]+'0';
if(count!=2)
{
fputc(ch,pointer1);
count++;
}
else
break;
i++;
}
getch();
}
this is only for a sample simple random number generation.....
thank u
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / dayquest
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void main()
{
int i;
randomize();
printf("\n Ten random numbers between 1 and 1000 are \n");
for(i=0;i<10;i++)
printf("%d ",random(1000)+1);
getch();
}
| Is This Answer Correct ? | 0 Yes | 2 No |
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