Answer / akshay p

#include<iostream.h>
#include<conio.h>
#include<stdlib.h>

void create(); // For creating a graph
void dfs(); // For Deapth First Search(DFS) Traversal.
void bfs(); // For Breadth First Search(BFS) Traversal.

struct node // Structure for elements in the graph
{
int data,status;
struct node *next;
struct link *adj;
};

struct link // Structure for adjacency list
{
struct node *next;
struct link *adj;
};

struct node *start,*p,*q;
struct link *l,*k;

int main()
{
int choice;
clrscr();
create();
while(1)
{
cout<<"-----------------------\n\n";
cout<<"1: DFS\n\n2: BSF\n\n3: Exit\n\nEnter
your choice: \n";
cin>>choice;
switch(choice)
{
case 1:
dfs();
break;
case 2:
bfs();
break;
case 3:
exit(0);
break;
default:
cout<<"Incorrect choice!Re-enter your
choice.";
getch();
}
}
return 0;
}

void create() // Creating a graph
{
int dat,flag=0;
start=NULL;
cout<<"Enter the nodes in the graph(0 to end): ";
while(1)
{
cin>>dat;
if(dat==0)
break;
p=new node;
p->data=dat;
p->status=0;
p->next=NULL;
p->adj=NULL;
if(flag==0)
{
start=p;
q=p;
flag++;
}
else
{
q->next=p;
q=p;
}
}
p=start;
while(p!=NULL)
{
cout<<"Enter the links to "<<p->data<<" (0 to
end) : ";
flag=0;
while(1)
{
cin>>dat;
if(dat==0)
break;
k=new link;
k->adj=NULL;
if(flag==0)
{
p->adj=k;
l=k;
flag++;
}
else
{
l->adj=k;
l=k;
}
q=start;
while(q!=NULL)
{
if(q->data==dat)
k->next=q;
q=q->next;
}
}
p=p->next;
}
cout<<"-------------------------";
return;
}


// Deapth First Search(DFS) Traversal.
void bfs()
{
int qu[20],i=1,j=0;
p=start;
while(p!=NULL)
{
p->status=0;
p=p->next;
}
p=start;
qu[0]=p->data;
p->status=1;
while(1)
{
if(qu[j]==0)
break;
p=start;
while(p!=NULL)
{
if(p->data==qu[j])
break;
p=p->next;
}
k=p->adj;
while(k!=NULL)
{
q=k->next;
if(q->status==0)
{
qu[i]=q->data;
q->status=1;
qu[i+1]=0;
i++;
}
k=k->adj;
}
j++;
}
j=0;
cout<<"Breadth First Search Results";
cout<<"---------------------------";
while(qu[j]!=0)
{
cout<<qu[j]<<" ";
j++;
}
getch();
return;
}


// Breadth First Search(BFS) Traversal.
void dfs()
{
int stack[25],top=1;
cout<<"Deapth First Search Results";
cout<<"---------------------------";
p=start;
while(p!=NULL)
{
p->status=0;
p=p->next;
}
p=start;
stack[0]=0;
stack[top]=p->data;
p->status=1;
while(1)
{
if(stack[top]==0)
break;
p=start;
while(p!=NULL)
{
if(p->data==stack[top])
break;
p=p->next;
}
cout<<stack[top]<<" ";
top--;
k=p->adj;
while(k!=NULL)
{
q=k->next;
if(q->status==0)
{
top++;
stack[top]=q->data;
q->status=1;
}
k=k->adj;
}
}
getch();
return;
}

Building Quotation engine program

5 Answers   Wipro,

---

I'm trying to solve this. But I'm not figuring the right solution. Can some one help what the answer is for the question below? You can use as many variables as you need, there are no negative numbers, all numbers are integers. You do not know the size of the integers, they could be infinitely large, so you can't count on truncating at any point. There are NO comparisons allowed, no if statements or anything like that. There are only four operations you can do on a variable. 1) You can set a variable to 0. 2) You can set a variable = another variable. 3) You can increment a variable (only by 1), and it's a post increment. 4) You can loop. So, if you were to say loop(v1) and v1 = 10, your loop would execute 10 times, but the value in v1 wouldn't change so the first line in the loop can change value of v1 without changing the number of times you loop. You need to do 3 things. 1) Write a function that decrements by 1. 2) Write a function that subtracts one variable from another. 3) Write a function that divides one variable by another. 4) See if you can implement all 3 using at most 4 variables. Meaning, you're not making function calls now, you're making macros. And at most you can have 4 variables. The restriction really only applies to divide, the other 2 are easy to do with 4 vars or less. Division on the other hand is dependent on the other 2 functions, so, if subtract requires 3 variables, then divide only has 1 variable left unchanged after a call to subtract. Basically, just make your function calls to decrement and subtract so you pass your vars in by reference, and you can't declare any new variables in a function, what you pass in is all it gets.

1 Answers   Microsoft,

---

How does the type system works when there is interoperability between a COM and .Net, i mean what exactly happens there

0 Answers   247Customer,

---

what are the missinschema properties and should we pass primary key in select command

0 Answers  

---

Who is providing best mainframes online training in Hyderabad

1 Answers  

---

How to create a new dataset only duplicate observations in proc sort procedure?

0 Answers   Accenture,

---

Is anyone has done the ASP.NET MVC4 workshop course(2 days) from Peers Technologies. Let me know. I need to talk before joining ASP.NET MVC4 training at peers, Hyderabad.

0 Answers  

---

V2 SOLUTIONS APTI paper is very easy there are 3 sections 1'st is quant problem on age train traveling speed is given length of train is given we have to find out length of bridge then prob on calender one date is given on Friday hv to find out day of othe date ans is Friday then there was 1 prob on percentage which was very easy ans was 21340 then 2’nd section was english grammer had has been being like that hv to fill in the blanks was very wasy then last section was find relative words there was five Q 1 pant ANS:-breath 2inquire ans :- ask And 3 more out of that 1 ‘s ans was:- body 4 And others ans was :-through THEN THEY HAVE GD There was three topics 1 should we allow india’s talent to go to abrod 2 protest against seperate state is justify 3 inturuption of politics in cricket Thats all guys i cleared both the rounds now preparing 4 interview best of luck

0 Answers   V2 Solutions,

---

HOW TO BREAK THE FIREWALL?

0 Answers   ME,

---

what is the filters in biztakk server? where it can use?

0 Answers   Wipro,

---

9.Difference between even and odd signals?explain with the diagram?

0 Answers  

---

what is the system development cycle

0 Answers  

---