Answer / akshay p

#include<iostream.h>
#include<conio.h>
#include<stdlib.h>

void create(); // For creating a graph
void dfs(); // For Deapth First Search(DFS) Traversal.
void bfs(); // For Breadth First Search(BFS) Traversal.

struct node // Structure for elements in the graph
{
int data,status;
struct node *next;
struct link *adj;
};

struct link // Structure for adjacency list
{
struct node *next;
struct link *adj;
};

struct node *start,*p,*q;
struct link *l,*k;

int main()
{
int choice;
clrscr();
create();
while(1)
{
cout<<"-----------------------\n\n";
cout<<"1: DFS\n\n2: BSF\n\n3: Exit\n\nEnter
your choice: \n";
cin>>choice;
switch(choice)
{
case 1:
dfs();
break;
case 2:
bfs();
break;
case 3:
exit(0);
break;
default:
cout<<"Incorrect choice!Re-enter your
choice.";
getch();
}
}
return 0;
}

void create() // Creating a graph
{
int dat,flag=0;
start=NULL;
cout<<"Enter the nodes in the graph(0 to end): ";
while(1)
{
cin>>dat;
if(dat==0)
break;
p=new node;
p->data=dat;
p->status=0;
p->next=NULL;
p->adj=NULL;
if(flag==0)
{
start=p;
q=p;
flag++;
}
else
{
q->next=p;
q=p;
}
}
p=start;
while(p!=NULL)
{
cout<<"Enter the links to "<<p->data<<" (0 to
end) : ";
flag=0;
while(1)
{
cin>>dat;
if(dat==0)
break;
k=new link;
k->adj=NULL;
if(flag==0)
{
p->adj=k;
l=k;
flag++;
}
else
{
l->adj=k;
l=k;
}
q=start;
while(q!=NULL)
{
if(q->data==dat)
k->next=q;
q=q->next;
}
}
p=p->next;
}
cout<<"-------------------------";
return;
}


// Deapth First Search(DFS) Traversal.
void bfs()
{
int qu[20],i=1,j=0;
p=start;
while(p!=NULL)
{
p->status=0;
p=p->next;
}
p=start;
qu[0]=p->data;
p->status=1;
while(1)
{
if(qu[j]==0)
break;
p=start;
while(p!=NULL)
{
if(p->data==qu[j])
break;
p=p->next;
}
k=p->adj;
while(k!=NULL)
{
q=k->next;
if(q->status==0)
{
qu[i]=q->data;
q->status=1;
qu[i+1]=0;
i++;
}
k=k->adj;
}
j++;
}
j=0;
cout<<"Breadth First Search Results";
cout<<"---------------------------";
while(qu[j]!=0)
{
cout<<qu[j]<<" ";
j++;
}
getch();
return;
}


// Breadth First Search(BFS) Traversal.
void dfs()
{
int stack[25],top=1;
cout<<"Deapth First Search Results";
cout<<"---------------------------";
p=start;
while(p!=NULL)
{
p->status=0;
p=p->next;
}
p=start;
stack[0]=0;
stack[top]=p->data;
p->status=1;
while(1)
{
if(stack[top]==0)
break;
p=start;
while(p!=NULL)
{
if(p->data==stack[top])
break;
p=p->next;
}
cout<<stack[top]<<" ";
top--;
k=p->adj;
while(k!=NULL)
{
q=k->next;
if(q->status==0)
{
top++;
stack[top]=q->data;
q->status=1;
}
k=k->adj;
}
}
getch();
return;
}

Hi guys... I have one doubt ..Exception is a runtime error then why we have checked exception... Thanks in advance

2 Answers  

---

What's the difference b/w Table & Templete in Smartform?

0 Answers   Accenture,

---

how we define two jobs have same name??is it exist??

0 Answers   CTS,

---

I'm trying to solve this. But I'm not figuring the right solution. Can some one help what the answer is for the question below? You can use as many variables as you need, there are no negative numbers, all numbers are integers. You do not know the size of the integers, they could be infinitely large, so you can't count on truncating at any point. There are NO comparisons allowed, no if statements or anything like that. There are only four operations you can do on a variable. 1) You can set a variable to 0. 2) You can set a variable = another variable. 3) You can increment a variable (only by 1), and it's a post increment. 4) You can loop. So, if you were to say loop(v1) and v1 = 10, your loop would execute 10 times, but the value in v1 wouldn't change so the first line in the loop can change value of v1 without changing the number of times you loop. You need to do 3 things. 1) Write a function that decrements by 1. 2) Write a function that subtracts one variable from another. 3) Write a function that divides one variable by another. 4) See if you can implement all 3 using at most 4 variables. Meaning, you're not making function calls now, you're making macros. And at most you can have 4 variables. The restriction really only applies to divide, the other 2 are easy to do with 4 vars or less. Division on the other hand is dependent on the other 2 functions, so, if subtract requires 3 variables, then divide only has 1 variable left unchanged after a call to subtract. Basically, just make your function calls to decrement and subtract so you pass your vars in by reference, and you can't declare any new variables in a function, what you pass in is all it gets.

1 Answers   Microsoft,

---

Data structure used to impliment a menu:

0 Answers   Verifone,

---

---

what is log files in qtp what is use

0 Answers   HSBC,

---

what is encapulation?

4 Answers   Syntel,

---

plz send me NIC Scientific Officer /Engineer-SB(Programmer) previous question paper or syllabus

2 Answers   NIC,

---

Difference between delegates and Events?

0 Answers  

---

ho&#65367;&#12288;&#65364;o check single or double byte in struts

0 Answers  

---

Which method protects back button to retrieve old value from previous page in Struts.

0 Answers  

---

write the a cl program with the following specification A. Accept 2 parameters-date and date type B. if date type is J then convert date to *MDY format C. if date type is M convert date to *JUL format 4.send a program message with the value of converted date Please explain for each with coding?

0 Answers  

---